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Mathematics
Mathematics
Problem
For the motion described by
s
(
t
)
=
5
+
2
t
4
s(t)=\sqrt{5+2t^{4}}
s
(
t
)
=
5
+
2
t
4
metres, what is the velocity of the particle at
t
=
1
s
t=1\,\text{s}
t
=
1
s
? a)
8
7
m s
−
1
\displaystyle \frac{8}{\sqrt{7}}\;\text{m s}^{-1}
7
8
m s
−
1
b)
2
7
m s
−
1
\displaystyle \frac{2}{\sqrt{7}}\;\text{m s}^{-1}
7
2
m s
−
1
c)
4
7
m s
−
1
\displaystyle \frac{4}{\sqrt{7}}\;\text{m s}^{-1}
7
4
m s
−
1
d)
4
7
m s
−
1
\displaystyle \frac{4}{7}\;\text{m s}^{-1}
7
4
m s
−
1
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