Introduction to Quantum Mechanics · Problem A.4

Afterword — David J. Griffiths

Physics — Quantum Mechanics · inner-products

Problem

Suppose you start out with a basis (∣e1⟩,∣e2⟩,…,∣en⟩)(|e_1\rangle, |e_2\rangle, \ldots, |e_n\rangle) that is not orthonormal. The Gram--Schmidt procedure is a systematic ritual for generating from it an orthonormal basis (∣e1′⟩,∣e2′⟩,…,∣en′⟩)(|e_1'\rangle, |e_2'\rangle, \ldots, |e_n'\rangle). It goes like this: (i) Normalize the first basis vector (divide by its norm): ∣e1′⟩=∣e1⟩∥e1∥.|e_1'\rangle = \frac{|e_1\rangle}{\|e_1\|}. (ii) Find the projection of the second vector along the first, and subtract it off: ∣e2⟩−⟨e1′∣e2⟩∣e1′⟩.|e_2\rangle - \langle e_1' \mid e_2\rangle |e_1'\rangle. This vector is orthogonal to ∣e1′⟩|e_1'\rangle; normalize it to get ∣e2′⟩|e_2'\rangle. (iii) Subtract from ∣e3⟩|e_3\rangle its projections along ∣e1′⟩|e_1'\rangle and ∣e2′⟩|e_2'\rangle: ∣e3⟩−⟨e1′∣e3⟩∣e1′⟩−⟨e2′∣e3⟩∣e2′⟩.|e_3\rangle - \langle e_1' \mid e_3\rangle |e_1'\rangle - \langle e_2' \mid e_3\rangle |e_2'\rangle. This is orthogonal to ∣e1′⟩|e_1'\rangle and ∣e2′⟩|e_2'\rangle; normalize it to get ∣e3′⟩|e_3'\rangle. And so on. Use the Gram--Schmidt procedure to orthonormalize the 3-space basis ∣e1⟩=(1+i)i^+(1)j^+(i)k^|e_1\rangle = (1+i)\hat{i} + (1)\hat{j} + (i)\hat{k}, ∣e2⟩=(i)i^+(3)j^+(1)k^|e_2\rangle = (i)\hat{i} + (3)\hat{j} + (1)\hat{k}, ∣e3⟩=(0)i^+(28)j^+(0)k^|e_3\rangle = (0)\hat{i} + (28)\hat{j} + (0)\hat{k}.

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