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Mathematics
Mathematics
Problem
Let
y
=
arctan
(
1
+
2
x
)
y=\arctan\!\big(\sqrt{1+2x}\big)
y
=
arctan
(
1
+
2
x
)
. Which equation gives the normal line to the graph at
x
=
2
x=2
x
=
2
? a)
y
−
arctan
(
5
)
=
1
6
5
(
x
−
2
)
y-\arctan(\sqrt{5})=\dfrac{1}{6\sqrt{5}}\,(x-2)
y
−
arctan
(
5
)
=
6
5
1
(
x
−
2
)
b)
y
−
arctan
(
5
)
=
6
5
(
x
−
2
)
y-\arctan(\sqrt{5})=6\sqrt{5}\,(x-2)
y
−
arctan
(
5
)
=
6
5
(
x
−
2
)
c)
y
−
arctan
(
5
)
=
−
6
5
(
x
−
2
)
y-\arctan(\sqrt{5})=-6\sqrt{5}\,(x-2)
y
−
arctan
(
5
)
=
−
6
5
(
x
−
2
)
d)
y
−
arctan
(
5
)
=
−
12
5
(
x
−
2
)
y-\arctan(\sqrt{5})=-12\sqrt{5}\,(x-2)
y
−
arctan
(
5
)
=
−
12
5
(
x
−
2
)
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