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Mathematics
Mathematics
Problem
Given
sin
θ
=
3
5
\sin\theta=\dfrac{3}{5}
sin
θ
=
5
3
and
θ
\theta
θ
lies in Quadrant II, find
cos
θ
\cos\theta
cos
θ
. a)
4
5
\dfrac{4}{5}
5
4
b)
−
4
5
-\dfrac{4}{5}
−
5
4
c)
−
3
5
-\dfrac{3}{5}
−
5
3
d)
−
2
5
-\dfrac{2}{5}
−
5
2
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