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Mathematics
Mathematics
Problem
The function
h
(
x
)
=
ln
x
+
1
x
h(x)=\ln x+\dfrac{1}{x}
h
(
x
)
=
ln
x
+
x
1
is continuous on
[
1
2
,
3
]
\left[\tfrac12,3\right]
[
2
1
,
3
]
. At which
x
x
x
-value does
h
h
h
attain its absolute maximum on this interval? a)
x
=
1
x=1
x
=
1
b)
h
h
h
has no absolute maximum
\,\,
on this interval c)
x
=
3
x=3
x
=
3
d)
x
=
2
x=2
x
=
2
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