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Mathematics
Mathematics
Problem
If
∑
i
=
1
n
cos
θ
i
=
n
\sum_{i=1}^{n} \cos \theta_i = n
∑
i
=
1
n
cos
θ
i
=
n
, then
∑
i
=
1
n
sin
θ
i
\sum_{i=1}^{n} \sin \theta_i
∑
i
=
1
n
sin
θ
i
is a.
n
−
1
n-1
n
−
1
b. 0 c.
n
n
n
d.
n
+
1
n+1
n
+
1
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