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Mathematics
Mathematics
Problem
If
2
f
(
x
)
+
f
(
−
x
)
=
1
x
sin
(
x
−
1
x
)
2f(x) + f(-x) = \frac{1}{x} \sin \left( x - \frac{1}{x} \right)
2
f
(
x
)
+
f
(
−
x
)
=
x
1
sin
(
x
−
x
1
)
, then the value of
∫
1
/
e
e
f
(
x
)
d
x
\int_{1/e}^{e} f(x) dx
∫
1/
e
e
f
(
x
)
d
x
is a. 0 b.
e
e
e
c.
1
/
e
1/e
1/
e
d.
e
+
1
/
e
e + 1/e
e
+
1/
e
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