Blundell Thermal Physics · Problem 25.3

Relativistic gases

Physics — Statistical Mechanics · general-dispersion-relation-partition-function

Problem

Consider a general dispersion relation of the form E=αps,(25.33)E = \alpha p^s,\tag{25.33} where pp is the momentum and α\alpha and ss are constants. Using the result of the previous question, show that the density of states as a function of energy is g(E) dE=gVDπD/2hDαD/ss Γ ⁣(D2+1)EDs−1 dE.(25.34)g(E)\,\mathrm{d}E = \frac{gVD\pi^{D/2}}{h^D \alpha^{D/s} s\,\Gamma\!\left(\frac{D}{2}+1\right)} E^{\frac{D}{s}-1}\,\mathrm{d}E.\tag{25.34} Hence show that the single-particle partition function takes the form Z1=VλD,(25.35)Z_1 = \frac{V}{\lambda^D},\tag{25.35} where λ\lambda is given by λ=hπ1/2(αkBT)1/s[Γ ⁣(D2+1)Γ ⁣(Ds+1)]1/D.(25.36)\lambda = \frac{h}{\pi^{1/2}}\left(\frac{\alpha}{k_\mathrm{B}T}\right)^{1/s}\left[\frac{\Gamma\!\left(\frac{D}{2}+1\right)}{\Gamma\!\left(\frac{D}{s}+1\right)}\right]^{1/D}.\tag{25.36} Show that this result for three dimensions (D=3D=3) agrees with (i) the non-relativistic case when s=2s=2 and (ii) the ultrarelativistic case when s=1s=1.

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