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Chemistry
Chemistry
Problem
An electric bulb of volume
250
cm
3
250 \text{ cm}^3
250
cm
3
was sealed off during manufacture at a pressure of
10
−
3
mm
10^{-3} \text{ mm}
1
0
−
3
mm
of mercury at 27°C. Compute the number of air molecules contained in the bulb. Given that
R
=
8.31
J/mol K
R = 8.31 \text{ J/mol K}
R
=
8.31
J/mol K
and
N
A
=
6.02
×
10
23
N_A = 6.02 \times 10^{23}
N
A
=
6.02
×
1
0
23
per mol.
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