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Mathematics
Mathematics
Problem
If
f
:
R
→
R
f: \mathbb{R} \to \mathbb{R}
f
:
R
→
R
,
f
(
x
)
=
x
2
+
b
x
+
1
x
2
+
2
x
+
b
f(x) = \frac{x^2 + bx + 1}{x^2 + 2x + b}
f
(
x
)
=
x
2
+
2
x
+
b
x
2
+
b
x
+
1
,
(
b
>
1
)
(b > 1)
(
b
>
1
)
and
f
(
x
)
,
1
f
(
x
)
f(x), \frac{1}{f(x)}
f
(
x
)
,
f
(
x
)
1
have the same bounded set as their range, the value of
b
b
b
is a.
2
3
−
2
2\sqrt{3} - 2
2
3
−
2
b.
2
3
+
2
2\sqrt{3} + 2
2
3
+
2
c.
2
2
−
2
2\sqrt{2} - 2
2
2
−
2
d.
2
2
+
2
2\sqrt{2} + 2
2
2
+
2
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