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Problem Determine the equation of the tangent line to the curve y = sin x y=\sin x y = sin x x = π / 6 x=\pi/6 x = π /6 y − 1 2 = 1 2 ( x − π 6 ) y-\dfrac12 = \dfrac12\left(x-\dfrac{\pi}{6}\right) y − 2 1 = 2 1 ( x − 6 π ) y − 1 2 = − 3 2 ( x − π 6 ) y-\dfrac12 = -\dfrac{\sqrt3}{2}\left(x-\dfrac{\pi}{6}\right) y − 2 1 = − 2 3 ( x − 6 π ) y − 1 2 = 3 2 ( x − π 6 ) y-\dfrac12 = \dfrac{\sqrt3}{2}\left(x-\dfrac{\pi}{6}\right) y − 2 1 = 2 3 ( x − 6 π ) y − 3 2 = 1 2 ( x − π 6 ) y-\dfrac{\sqrt3}{2} = \dfrac12\left(x-\dfrac{\pi}{6}\right) y − 2 3 = 2 1 ( x − 6 π ) Browse the problem library