The expression for waveguide parameter is given as follows: V=\frac{2... · PHYSICS Dataset #8161

Physics · optics

Problem

The expression for waveguide parameter VV is given as follows: V=2πλ0dn12−n22V=\frac{2 \pi}{\lambda_{0}} d \sqrt{n_{1}^{2}-n_{2}^{2}} Here, dd is the width, λ0\lambda_{0} is the operational wavelength, n1n_{1} and n2n_{2} are the indexes of refractions. Substitute n1=1.50n_{1}=1.50, n2=1.46n_{2}=1.46, λ0=0.6328 μ m\lambda_{0}=0.6328 \ \mu \mathrm{~m}, and d=4 μ md=4 \ \mu \mathrm{~m} to calculate VV.

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