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Mathematics
Problem
Show that
sin
2
5
∘
+
sin
2
10
∘
+
sin
2
15
∘
+
⋯
+
sin
2
90
∘
=
9
1
2
\sin^2 5^\circ + \sin^2 10^\circ + \sin^2 15^\circ + \dots + \sin^2 90^\circ = 9\frac{1}{2}
sin
2
5
∘
+
sin
2
1
0
∘
+
sin
2
1
5
∘
+
⋯
+
sin
2
9
0
∘
=
9
2
1
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