Problem

Problem

If lim⁡x→∞(x2+x+1x+1−ax−b)=4\lim_{x \to \infty} \left( \frac{x^2 + x + 1}{x + 1} - ax - b \right) = 4 , then a. a=1,b=4a = 1, b = 4 b. a=1,b=−4a = 1, b = -4 c. a=2,b=−3a = 2, b = -3 d. a=2,b=3a = 2, b = 3

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