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Mathematics
Mathematics
Problem
Solve for
θ
\theta
θ
(in degrees) if
0
∘
≤
θ
<
360
∘
0^{\circ} \le \theta < 360^{\circ}
0
∘
≤
θ
<
36
0
∘
and
sin
θ
=
1
2
\sin \theta = \dfrac{1}{2}
sin
θ
=
2
1
.
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