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Mathematics
Mathematics
Problem
Let
g
(
x
)
=
x
−
2
k
g(x) = \sqrt{x - 2k}
g
(
x
)
=
x
−
2
k
,
∀
2
k
≤
x
<
2
(
k
+
1
)
\forall 2k \le x < 2(k+1)
∀2
k
≤
x
<
2
(
k
+
1
)
where,
k
∈
I
k \in I
k
∈
I
, then a.
g
(
x
)
=
x
+
2
g(x) = \sqrt{x+2}
g
(
x
)
=
x
+
2
,
−
2
≤
x
<
0
-2 \le x < 0
−
2
≤
x
<
0
b.
g
(
x
)
=
x
−
2
g(x) = \sqrt{x-2}
g
(
x
)
=
x
−
2
,
2
≤
x
<
4
2 \le x < 4
2
≤
x
<
4
c.
g
(
x
)
=
x
g(x) = \sqrt{x}
g
(
x
)
=
x
,
0
≤
x
<
2
0 \le x < 2
0
≤
x
<
2
d. period of
g
(
x
)
g(x)
g
(
x
)
is 2.
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