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Physics
Physics
Problem
A body performs SHM according to
x
(
t
)
=
0.05
cos
(
8
π
t
+
π
/
3
)
x(t)=0.05\cos(8\pi t+\pi/3)
x
(
t
)
=
0.05
cos
(
8
π
t
+
π
/3
)
, where
x
x
x
is in metres and
t
t
t
in seconds. The displacement of the body at
t
=
0.25
s
t=0.25\,\text{s}
t
=
0.25
s
is a)
+
0.050
m
+0.050\,\text{m}
+
0.050
m
b)
−
0.025
m
-0.025\,\text{m}
−
0.025
m
c)
+
0.025
m
+0.025\,\text{m}
+
0.025
m
d)
+
0.043
m
+0.043\,\text{m}
+
0.043
m
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