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Mathematics
Mathematics
Problem
If
x
d
y
d
x
=
y
(
log
y
−
log
x
+
1
)
x \frac{dy}{dx} = y(\log y - \log x + 1)
x
d
x
d
y
=
y
(
lo
g
y
−
lo
g
x
+
1
)
, then the solution of equation is (a)
y
log
(
x
y
)
=
c
x
y \log \left( \frac{x}{y} \right) = cx
y
lo
g
(
y
x
)
=
c
x
(b)
x
log
(
y
x
)
=
c
y
x \log \left( \frac{y}{x} \right) = cy
x
lo
g
(
x
y
)
=
cy
(c)
log
(
y
x
)
=
c
x
\log \left( \frac{y}{x} \right) = cx
lo
g
(
x
y
)
=
c
x
(d)
log
(
x
y
)
=
c
y
\log \left( \frac{x}{y} \right) = cy
lo
g
(
y
x
)
=
cy
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