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Chemistry
Chemistry
Problem
What is the E.M.F. of the cell, given
E
A
/
A
+
∘
=
0.35
V
E^{\circ}_{\text{A}/\text{A}^+} = 0.35\,\text{V}
E
A
/
A
+
∘
=
0.35
V
and
E
B
/
B
+
∘
=
−
0.42
V
E^{\circ}_{\text{B}/\text{B}^+} = -0.42\,\text{V}
E
B
/
B
+
∘
=
−
0.42
V
? The cell has the electrodes A and B in their respective electrolytes. (a)
+
0.07
V
+0.07\,\text{V}
+
0.07
V
(b)
−
0.07
V
-0.07\,\text{V}
−
0.07
V
(c)
+
0.77
V
+0.77\,\text{V}
+
0.77
V
(d)
−
0.77
V
-0.77\,\text{V}
−
0.77
V
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