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Mathematics
Problem
Show that the derivative of
g
(
x
)
=
1
x
g(x)=\dfrac{1}{x}
g
(
x
)
=
x
1
is
g
′
(
x
)
=
−
1
x
2
g'(x)=-\dfrac{1}{x^{2}}
g
′
(
x
)
=
−
x
2
1
.
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