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Mathematics
Mathematics
Problem
If the solutions for
θ
\theta
θ
from the equation
sin
2
θ
−
2
sin
θ
+
λ
=
0
\sin^2 \theta - 2\sin \theta + \lambda = 0
sin
2
θ
−
2
sin
θ
+
λ
=
0
lie in
⋃
n
∈
Z
(
2
n
π
−
π
6
,
(
2
n
+
1
)
π
+
π
6
)
\bigcup_{n \in \mathbb{Z}} \left(2n\pi - \frac{\pi}{6}, (2n+1)\pi + \frac{\pi}{6}\right)
⋃
n
∈
Z
(
2
nπ
−
6
π
,
(
2
n
+
1
)
π
+
6
π
)
. Then, find the possible set values of
λ
\lambda
λ
.
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