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Mathematics
Mathematics
Problem
If the line
2
x
+
6
y
=
2
2x + \sqrt{6}y = 2
2
x
+
6
y
=
2
touches the hyperbola
x
2
−
2
y
2
=
4
x^2 - 2y^2 = 4
x
2
−
2
y
2
=
4
, then the point of contact is a.
(
−
2
,
6
)
(-2, \sqrt{6})
(
−
2
,
6
)
b.
(
−
5
,
2
6
)
(-5, 2\sqrt{6})
(
−
5
,
2
6
)
c.
(
1
2
,
1
6
)
\left(\frac{1}{2}, \frac{1}{\sqrt{6}}\right)
(
2
1
,
6
1
)
d.
(
4
,
−
6
)
(4, -\sqrt{6})
(
4
,
−
6
)
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