Let g(x)=x−25x−5, defined for x>0. Which of the following statements about x→25limg(x) is true?
a) The limit is 0 because the numerator approaches 0 faster than the denominator.
b) Both one-sided limits exist and equal 101; therefore the limit equals 101.
c) The limit does not exist because the expression becomes the indeterminate form 0/0 at x=25.
d) After simplification, the limit equals 51.