Mathematics

Mathematics

Problem

Let g(x)=x−5x−25g(x)=\dfrac{\sqrt{x}-5}{x-25}, defined for x>0x>0. Which of the following statements about lim⁡x→25g(x)\displaystyle\lim_{x\to25} g(x) is true? a) The limit is 00 because the numerator approaches 00 faster than the denominator. b) Both one-sided limits exist and equal 110\dfrac{1}{10}; therefore the limit equals 110\dfrac{1}{10}. c) The limit does not exist because the expression becomes the indeterminate form 0/00/0 at x=25x=25. d) After simplification, the limit equals 15\dfrac{1}{5}.

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