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Mathematics
Mathematics
Problem
If the shortest distance of the parabola
y
2
=
4
x
y^2 = 4x
y
2
=
4
x
from the centre of the circle
x
2
+
y
2
−
4
x
−
16
y
+
64
=
0
x^2 + y^2 - 4x - 16y + 64 = 0
x
2
+
y
2
−
4
x
−
16
y
+
64
=
0
is
d
d
d
, then
d
2
d^2
d
2
is equal to (2024 Main, 27 Jan I) (a) 24 (b) 16 (c) 20 (d) 36
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