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Mathematics
Problem
The domain of derivative of the function
f
(
x
)
=
∣
sin
−
1
(
2
x
2
−
1
)
∣
f(x) = |\sin^{-1}(2x^2 - 1)|
f
(
x
)
=
∣
sin
−
1
(
2
x
2
−
1
)
∣
, is a.
(
−
1
,
1
)
(-1, 1)
(
−
1
,
1
)
b.
(
−
1
,
1
)
−
{
0
,
±
1
2
}
(-1, 1) - \left\{0, \pm \frac{1}{\sqrt{2}}\right\}
(
−
1
,
1
)
−
{
0
,
±
2
1
}
c.
(
−
1
,
1
)
−
{
0
}
(-1, 1) - \{0\}
(
−
1
,
1
)
−
{
0
}
d.
(
−
1
,
1
)
−
{
±
1
2
}
(-1, 1) - \left\{\pm \frac{1}{\sqrt{2}}\right\}
(
−
1
,
1
)
−
{
±
2
1
}
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