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Mathematics
Mathematics
Problem
d
d
x
[
log
(
x
+
1
x
)
]
=
\frac{d}{dx} \left[\log \left(x + \frac{1}{x}\right)\right] =
d
x
d
[
lo
g
(
x
+
x
1
)
]
=
(a)
(
x
+
1
x
)
\left(x + \frac{1}{x}\right)
(
x
+
x
1
)
(b)
(
1
+
1
x
2
)
(
1
+
1
x
)
\frac{\left(1 + \frac{1}{x^2}\right)}{\left(1 + \frac{1}{x}\right)}
(
1
+
x
1
)
(
1
+
x
2
1
)
(c)
(
1
−
1
x
2
)
(
x
+
1
x
)
\frac{\left(1 - \frac{1}{x^2}\right)}{\left(x + \frac{1}{x}\right)}
(
x
+
x
1
)
(
1
−
x
2
1
)
(d)
(
1
+
1
x
)
\left(1 + \frac{1}{x}\right)
(
1
+
x
1
)
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