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Physics
Physics
Problem
Steel ruptures when a shear of
3.5
×
10
8
N m
−
2
3.5 \times 10^8 \text{ N m}^{-2}
3.5
×
1
0
8
N m
−
2
is applied. The force needed to punch a 1 cm diameter hole in a steel sheet 0.3 cm thick is nearly: a.
1.4
×
10
4
N
1.4 \times 10^4 \text{ N}
1.4
×
1
0
4
N
b.
2.7
×
10
4
N
2.7 \times 10^4 \text{ N}
2.7
×
1
0
4
N
c.
3.3
×
10
4
N
3.3 \times 10^4 \text{ N}
3.3
×
1
0
4
N
d.
1.1
×
10
4
N
1.1 \times 10^4 \text{ N}
1.1
×
1
0
4
N
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