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Mathematics
Problem
A population satisfies the differential equation
d
y
d
t
=
k
y
\frac{dy}{dt}=ky
d
t
d
y
=
k
y
with
y
(
1
)
=
200
y(1)=200
y
(
1
)
=
200
and
y
(
3
)
=
320
y(3)=320
y
(
3
)
=
320
. Determine (i) the value of
k
k
k
and (ii) the ratio of the instantaneous growth rate at
t
=
3
t=3
t
=
3
to that at
t
=
1
t=1
t
=
1
.
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