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Mathematics
Mathematics
Problem
If the sum of the first 20 terms of the series
log
(
7
1
/
2
)
x
+
log
(
7
1
/
3
)
x
+
log
(
7
1
/
4
)
x
+
…
\log_{(7^{1/2})} x + \log_{(7^{1/3})} x + \log_{(7^{1/4})} x + \dots
lo
g
(
7
1/2
)
x
+
lo
g
(
7
1/3
)
x
+
lo
g
(
7
1/4
)
x
+
…
is 460, then
x
x
x
is equal to (a)
7
2
7^2
7
2
(b)
7
1
/
2
7^{1/2}
7
1/2
(c)
e
2
e^2
e
2
(d)
7
46
/
21
7^{46/21}
7
46/21
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