Mathematics

Mathematics

Problem

If the sum of the first 20 terms of the series log⁡(71/2)x+log⁡(71/3)x+log⁡(71/4)x+…\log_{(7^{1/2})} x + \log_{(7^{1/3})} x + \log_{(7^{1/4})} x + \dots is 460, then xx is equal to (a) 727^2 (b) 71/27^{1/2} (c) e2e^2 (d) 746/217^{46/21}

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