Chemistry

Problem

For two I order reactions:

A \to B;\ k_1 = 10^{15} e^{-\frac{2 \times 10^3}{T}}

and

C \to D;\ k_2 = 10^{14} e^{-\frac{10^3}{T}}

. The temperature at which both have same rate if

[A] = [C]

is made initially: a.

707.2^\circ\text{C}

434.2^\circ\text{C}

727^\circ\text{C}

707.2 \text{ K}