Let $f(x) = \begin{cases} x^2 + 4x, & -3 \le x \le 0 \\ -\sin x, & 0 < x \le \frac{\pi}{2} \\ -\cos x - 1, & \frac{\pi}{2} < x \le \pi \end{cases}$ …

Problem

Let

f(x) = \begin{cases} x^2 + 4x, & -3 \le x \le 0 \\ -\sin x, & 0 < x \le \frac{\pi}{2} \\ -\cos x - 1, & \frac{\pi}{2} < x \le \pi \end{cases}

. Then, a.

x = -2

is the point of global minima b.

x = \pi

is the point of global maxima c.

f(x)

is non-differentiable at

x = \frac{\pi}{2}

f(x)

is discontinuous at

x = 0