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Physics
Physics
Problem
The relation between time 't' and distance 'x' is
t
=
α
x
2
+
β
x
t = \alpha x^2 + \beta x
t
=
α
x
2
+
β
x
, where
α
\alpha
α
and
β
\beta
β
are constants. The relation between acceleration (a) and velocity (v) is: (1)
a
=
−
2
α
v
3
a = -2\alpha v^3
a
=
−
2
α
v
3
(2)
a
=
−
5
α
v
3
a = -5\alpha v^3
a
=
−
5
α
v
3
(3)
a
=
−
3
α
v
2
a = -3\alpha v^2
a
=
−
3
α
v
2
(4)
a
=
−
4
α
v
4
a = -4\alpha v^4
a
=
−
4
α
v
4
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