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Chemistry
Chemistry
Problem
For a reaction with
E
a
,
fwd
=
150
kJ mol
−
1
E_{a,\text{fwd}} = 150\,\text{kJ mol}^{-1}
E
a
,
fwd
=
150
kJ mol
−
1
and
Δ
H
=
+
35
kJ mol
−
1
\Delta H = +35\,\text{kJ mol}^{-1}
Δ
H
=
+
35
kJ mol
−
1
, calculate the activation energy for the reverse reaction,
E
a
,
rev
E_{a,\text{rev}}
E
a
,
rev
, in
kJ mol
−
1
\text{kJ mol}^{-1}
kJ mol
−
1
.
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