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Mathematics
Problem
For the differential equation
d
y
d
x
=
r
y
(
1
−
y
6
)
−
s
\dfrac{dy}{dx}=r y\left(1-\dfrac{y}{6}\right)-s
d
x
d
y
=
r
y
(
1
−
6
y
)
−
s
with constants
r
>
0
r>0
r
>
0
and
s
≥
0
s\ge 0
s
≥
0
, determine the value of
s
s
s
(in terms of
r
r
r
) that makes
y
=
3
y=3
y
=
3
an equilibrium solution.
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