Mathematics

Mathematics

Problem

The transverse axis of a hyperbola is of length 2a2a and a vertex divides the segment of the axis between the centre and the corresponding focus in the ratio 2 : 1, then the equation of the hyperbola is a. 4x2−5y2=4a24x^2 - 5y^2 = 4a^2 b. 4x2−5y2=5a24x^2 - 5y^2 = 5a^2 c. 5x2−4y2=4a25x^2 - 4y^2 = 4a^2 d. 5x2−4y2=5a25x^2 - 4y^2 = 5a^2

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