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Mathematics
Problem
A plane
2
x
+
3
y
+
5
z
=
1
2x + 3y + 5z = 1
2
x
+
3
y
+
5
z
=
1
has a point
P
P
P
which is at minimum distance from line joining
A
(
1
,
0
,
−
3
)
,
B
(
1
,
−
5
,
7
)
A(1, 0, -3), B(1, -5, 7)
A
(
1
,
0
,
−
3
)
,
B
(
1
,
−
5
,
7
)
, then distance
A
P
AP
A
P
is equal to a.
3
5
3\sqrt{5}
3
5
b.
2
5
2\sqrt{5}
2
5
c.
4
5
4\sqrt{5}
4
5
d. None of these
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