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Mathematics
Mathematics
Problem
Find the domain of
y
=
sec
x
y=\sec x
y
=
sec
x
for
x
∈
[
0
,
2
π
)
x\in[0,2\pi)
x
∈
[
0
,
2
π
)
. a)
{
x
∈
[
0
,
2
π
)
∣
x
≠
0
,
π
}
\{x\in[0,2\pi)\mid x\neq0,\pi\}
{
x
∈
[
0
,
2
π
)
∣
x
=
0
,
π
}
b)
{
x
∈
[
0
,
2
π
)
∣
x
≠
π
2
,
π
,
3
π
2
}
\{x\in[0,2\pi)\mid x\neq\dfrac{\pi}{2},\pi,\dfrac{3\pi}{2}\}
{
x
∈
[
0
,
2
π
)
∣
x
=
2
π
,
π
,
2
3
π
}
c)
{
x
∈
[
0
,
2
π
)
∣
x
≠
π
2
,
3
π
2
}
\{x\in[0,2\pi)\mid x\neq\dfrac{\pi}{2},\dfrac{3\pi}{2}\}
{
x
∈
[
0
,
2
π
)
∣
x
=
2
π
,
2
3
π
}
d)
{
x
∈
[
0
,
2
π
)
∣
x
≠
π
2
}
\{x\in[0,2\pi)\mid x\neq\dfrac{\pi}{2}\}
{
x
∈
[
0
,
2
π
)
∣
x
=
2
π
}
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