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Chemistry
Chemistry
Problem
The molar enthalpy of fusion of benzene is
9.95
kJ mol
−
1
9.95\,\text{kJ mol}^{-1}
9.95
kJ mol
−
1
. Which of the following is the molar enthalpy change for freezing liquid benzene at its normal freezing point? a)
−
4.98
kJ mol
−
1
-4.98\,\text{kJ mol}^{-1}
−
4.98
kJ mol
−
1
b)
−
9.95
kJ mol
−
1
-9.95\,\text{kJ mol}^{-1}
−
9.95
kJ mol
−
1
c)
+
19.9
kJ mol
−
1
+19.9\,\text{kJ mol}^{-1}
+
19.9
kJ mol
−
1
d)
+
9.95
kJ mol
−
1
+9.95\,\text{kJ mol}^{-1}
+
9.95
kJ mol
−
1
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