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Mathematics
Problem
Let
y
(
x
)
=
7
+
∫
2
x
sin
t
d
t
y(x)=7+\displaystyle\int_{2}^{x}\!\sin t\,dt
y
(
x
)
=
7
+
∫
2
x
sin
t
d
t
. Without evaluating the integral, explain why
y
(
2
)
=
7
y(2)=7
y
(
2
)
=
7
.
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