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Mathematics
Mathematics
Problem
The Maclaurin series of a differentiable function
g
g
g
begins
g
(
x
)
=
3
+
0
⋅
x
+
5
24
x
4
+
⋯
.
g(x)=3+0\cdot x+\frac{5}{24}x^{4}+\cdots.
g
(
x
)
=
3
+
0
⋅
x
+
24
5
x
4
+
⋯
.
Explain what the coefficient
5
24
\frac{5}{24}
24
5
implies about
g
(
4
)
(
0
)
g^{(4)}(0)
g
(
4
)
(
0
)
and state that value.
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