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Mathematics
Mathematics
Problem
If
y
=
log
(
1
+
x
1
−
x
)
1
/
4
−
1
2
tan
−
1
x
y = \log\left(\frac{1+x}{1-x}\right)^{1/4} - \frac{1}{2} \tan^{-1} x
y
=
lo
g
(
1
−
x
1
+
x
)
1/4
−
2
1
tan
−
1
x
, then
d
y
d
x
=
\frac{dy}{dx} =
d
x
d
y
=
(a)
x
2
1
−
x
4
\frac{x^2}{1 - x^4}
1
−
x
4
x
2
(b)
2
x
2
1
−
x
4
\frac{2x^2}{1 - x^4}
1
−
x
4
2
x
2
(c)
x
2
2
(
1
−
x
4
)
\frac{x^2}{2(1 - x^4)}
2
(
1
−
x
4
)
x
2
(d) None of these
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