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Mathematics
Problem
The position of a particle moving along a line is
p
(
t
)
=
2
t
3
−
9
t
2
+
12
t
p(t)=2t^{3}-9t^{2}+12t
p
(
t
)
=
2
t
3
−
9
t
2
+
12
t
meters for
t
≥
0
t\ge 0
t
≥
0
. What is the particle’s instantaneous acceleration at
t
=
2
t=2
t
=
2
seconds? a)
−
6
m/s
2
-6\ \text{m/s}^2
−
6
m/s
2
b)
0
m/s
2
0\ \text{m/s}^2
0
m/s
2
c)
6
m/s
2
6\ \text{m/s}^2
6
m/s
2
d)
18
m/s
2
18\ \text{m/s}^2
18
m/s
2
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