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Problem
Problem
In
△
A
B
C
\triangle ABC
△
A
B
C
, if
a
c
=
3
ac = 3
a
c
=
3
,
b
c
=
4
bc = 4
b
c
=
4
and
cos
(
A
−
B
)
=
3
4
\cos(A - B) = \frac{3}{4}
cos
(
A
−
B
)
=
4
3
, then a. measure of
∠
A
\angle A
∠
A
is
π
2
\frac{\pi}{2}
2
π
b. measure of
∠
B
\angle B
∠
B
is
π
2
\frac{\pi}{2}
2
π
c.
cot
C
2
=
7
\cot \frac{C}{2} = \sqrt{7}
cot
2
C
=
7
d. circumradius of
△
A
B
C
\triangle ABC
△
A
B
C
is
2
7
1
/
4
\frac{2}{7^{1/4}}
7
1/4
2
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