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Physics
Physics
Problem
A particle is thrown vertically upward with initial velocity
u
u
u
and moves under a constant downward acceleration
g
g
g
. Using either
v
2
=
u
2
+
2
a
s
v^2 = u^2 + 2as
v
2
=
u
2
+
2
a
s
or by integrating
v
d
v
=
a
d
s
v\,dv = a\,ds
v
d
v
=
a
d
s
, derive the expression for the maximum height
H
H
H
reached by the particle.
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