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Mathematics
Mathematics
Problem
∫
sin
2
x
sin
4
x
+
cos
4
x
d
x
=
\int \frac{\sin 2x}{\sin^4 x + \cos^4 x}\,dx =
∫
s
i
n
4
x
+
c
o
s
4
x
s
i
n
2
x
d
x
=
(a)
cot
−
1
(
tan
2
x
)
+
c
\cot^{-1}(\tan^2 x) + c
cot
−
1
(
tan
2
x
)
+
c
(b)
tan
−
1
(
tan
2
x
)
+
c
\tan^{-1}(\tan^2 x) + c
tan
−
1
(
tan
2
x
)
+
c
(c)
cot
−
1
(
cot
2
x
)
+
c
\cot^{-1}(\cot^2 x) + c
cot
−
1
(
cot
2
x
)
+
c
(d)
tan
−
1
(
cot
2
x
)
+
c
\tan^{-1}(\cot^2 x) + c
tan
−
1
(
cot
2
x
)
+
c
(a)
cot
−
1
(
tan
2
x
)
+
c
\cot^{-1}(\tan^2 x) + c
cot
−
1
(
tan
2
x
)
+
c
(b)
tan
−
1
(
tan
2
x
)
+
c
\tan^{-1}(\tan^2 x) + c
tan
−
1
(
tan
2
x
)
+
c
(c)
cot
−
1
(
cot
2
x
)
+
c
\cot^{-1}(\cot^2 x) + c
cot
−
1
(
cot
2
x
)
+
c
(d)
tan
−
1
(
cot
2
x
)
+
c
\tan^{-1}(\cot^2 x) + c
tan
−
1
(
cot
2
x
)
+
c
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