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Chemistry
Chemistry
Problem
The solubility product constant of
AgCl
\text{AgCl}
AgCl
at 25 °C is
K
s
p
=
1.8
×
10
−
10
K_{sp}=1.8\times10^{-10}
K
s
p
=
1.8
×
1
0
−
10
. What is the molar solubility of
AgCl
\text{AgCl}
AgCl
in pure water at this temperature? a)
1.3
×
10
−
4
M
1.3\times10^{-4}\,\text{M}
1.3
×
1
0
−
4
M
b)
1.3
×
10
−
5
M
1.3\times10^{-5}\,\text{M}
1.3
×
1
0
−
5
M
c)
6.7
×
10
−
6
M
6.7\times10^{-6}\,\text{M}
6.7
×
1
0
−
6
M
d)
1.8
×
10
−
10
M
1.8\times10^{-10}\,\text{M}
1.8
×
1
0
−
10
M
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