Mathematics

Mathematics

Problem

The velocity of a particle is given by v(t)=t2−4t+3v(t)=t^{2}-4t+3 for t≥1t\ge 1. If the particle’s position at t=1t=1 is 55, which of the following is the particle’s position function s(t)s(t) for t≥1t\ge 1? a) s(t)=13t3−2t2+3ts(t)=\dfrac13 t^{3}-2t^{2}+3t b) s(t)=13t3−2t2+3t−113s(t)=\dfrac13 t^{3}-2t^{2}+3t-\dfrac{11}{3} c) s(t)=13t3−2t2+3t+113s(t)=\dfrac13 t^{3}-2t^{2}+3t+\dfrac{11}{3} d) s(t)=13t3−4t2+3t+173s(t)=\dfrac13 t^{3}-4t^{2}+3t+\dfrac{17}{3}

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