Mathematics

Mathematics

Problem

On the interval 0≤t≤50\le t\le 5 seconds a particle’s velocity satisfies ∫05v(t) dt=−2 ft\displaystyle \int_{0}^{5} v(t)\,dt = -2\text{ ft} while ∫05∣v(t)∣ dt=10 ft\displaystyle \int_{0}^{5} |v(t)|\,dt = 10\text{ ft}. Explain what these two values reveal about the particle’s motion during this time period.

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