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Mathematics
Mathematics
Problem
On the interval
0
≤
t
≤
5
0\le t\le 5
0
≤
t
≤
5
seconds a particle’s velocity satisfies
∫
0
5
v
(
t
)
d
t
=
−
2
ft
\displaystyle \int_{0}^{5} v(t)\,dt = -2\text{ ft}
∫
0
5
v
(
t
)
d
t
=
−
2
ft
while
∫
0
5
∣
v
(
t
)
∣
d
t
=
10
ft
\displaystyle \int_{0}^{5} |v(t)|\,dt = 10\text{ ft}
∫
0
5
∣
v
(
t
)
∣
d
t
=
10
ft
. Explain what these two values reveal about the particle’s motion during this time period.
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