Mathematics

Mathematics

Problem

Let a triangle be bounded by the lines L1:2x+5y=10L_1: 2x + 5y = 10; L2:−4x+3y=12L_2: -4x + 3y = 12 and the line L3L_3, which passes through the point P(2,3)P(2, 3), intersect L2L_2 at AA and L1L_1 at BB. If the point PP divides the line-segment ABAB, internally in the ratio 1:31:3, then the area of the triangle is equal to (a) 11013\frac{110}{13} (b) 13213\frac{132}{13} (c) 14212\frac{142}{12} (d) 15112\frac{151}{12}

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