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Mathematics
Mathematics
Problem
If the tangent at the point
(
2
sec
ϕ
,
3
tan
ϕ
)
(2\sec\phi, 3\tan\phi)
(
2
sec
ϕ
,
3
tan
ϕ
)
of the hyperbola
x
2
4
−
y
2
9
=
1
\frac{x^2}{4} - \frac{y^2}{9} = 1
4
x
2
−
9
y
2
=
1
is parallel to
3
x
−
y
+
4
=
0
3x - y + 4 = 0
3
x
−
y
+
4
=
0
, then the value of
ϕ
\phi
ϕ
is a.
π
6
\frac{\pi}{6}
6
π
b.
π
4
\frac{\pi}{4}
4
π
c.
π
3
\frac{\pi}{3}
3
π
d.
5
π
12
\frac{5\pi}{12}
12
5
π
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