Mathematics

Mathematics

Problem

If the tangent at the point (2sec⁡ϕ,3tan⁡ϕ)(2\sec\phi, 3\tan\phi) of the hyperbola x24−y29=1\frac{x^2}{4} - \frac{y^2}{9} = 1 is parallel to 3x−y+4=03x - y + 4 = 0 , then the value of ϕ\phi is a. π6\frac{\pi}{6} b. π4\frac{\pi}{4} c. π3\frac{\pi}{3} d. 5π12\frac{5\pi}{12}

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